(9x+5)/(x^2-9x+20)-(9)/(x-5)

Simple and best practice solution for (9x+5)/(x^2-9x+20)-(9)/(x-5) equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for (9x+5)/(x^2-9x+20)-(9)/(x-5) equation:


D( x )

x-5 = 0

x^2-(9*x)+20 = 0

x-5 = 0

x-5 = 0

x-5 = 0 // + 5

x = 5

x^2-(9*x)+20 = 0

x^2-(9*x)+20 = 0

x^2-9*x+20 = 0

x^2-9*x+20 = 0

DELTA = (-9)^2-(1*4*20)

DELTA = 1

DELTA > 0

x = (1^(1/2)+9)/(1*2) or x = (9-1^(1/2))/(1*2)

x = 5 or x = 4

x in (-oo:4) U (4:5) U (5:+oo)

(9*x+5)/(x^2-(9*x)+20)-(9/(x-5)) = 0

(9*x+5)/(x^2-9*x+20)-9*(x-5)^-1 = 0

(9*x+5)/(x^2-9*x+20)-9/(x-5) = 0

x^2-9*x+20 = 0

x^2-9*x+20 = 0

x^2-9*x+20 = 0

DELTA = (-9)^2-(1*4*20)

DELTA = 1

DELTA > 0

x = (1^(1/2)+9)/(1*2) or x = (9-1^(1/2))/(1*2)

x = 5 or x = 4

(x-4)*(x-5) = 0

(9*x+5)/((x-4)*(x-5))-9/(x-5) = 0

(9*x+5)/((x-4)*(x-5))+(-9*(x-4))/((x-4)*(x-5)) = 0

9*x-9*(x-4)+5 = 0

41 = 0

41/((x-4)*(x-5)) = 0

41/((x-4)*(x-5)) = 0 // * (x-4)*(x-5)

41 = 0

x belongs to the empty set

See similar equations:

| 4/5x=-2y | | x^5+x^2-12x=0 | | -6+(-75)= | | Y=x^3+x^2-42x | | 2x^2=16x-15 | | 12y-9x=-48 | | 6y=5y-2 | | 4x-1/4=5/2 | | (3x-3)*2-(2x-7)=(3x+5)(3x+5) | | -2y-2x=10 | | 3y+2xy=14 | | 3x-7/2=8/3 | | 2/3x27-7 | | 2/3x27-7 | | -5=-2x-y | | 7-4(x-6)=8-4(x-3) | | 7x/2-3/2-4/1=5x/3+1/3 | | 10u^7-45u^6+45u^5=0 | | 7-4(0-6)=8-4(0-3) | | 4(c-5)-2(3c+5)=6 | | 9y=-12x-18 | | 7-4(-11-6)=8-4(-11-3) | | 9-6(4u-1)=1u+15 | | a-21=42 | | 0=-y-2 | | x^3-6x=7 | | 5/4x-5/3=-3 | | 1/2(x+4)=x^2+2 | | 4/7x-2/7=-12 | | -x+4y=25 | | 240/60= | | 10+2/3t=6 |

Equations solver categories